按《同杆并架多回线下方的电场强度和感应电压》 做,想和“设计手册”例题2-1比较,做了一半没有继续下去。
Signed-off-by: dmy@lab <dmy@lab.com>
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Field.m
69
Field.m
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@ -4,48 +4,35 @@
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%%
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clc
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clear
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%电压(复数,至上到下,先左后右)
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%双回
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Volt=[220; 220*exp(1j*240*pi/180); 220*exp(1j*120*pi/180);220; 220*exp(1j*240*pi/180); 220*exp(1j*120*pi/180) ];
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%坐标,单回
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ConductorX=[-9,0,9];
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ConductorY=[14.5,14.5,14.5];
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%计算H,导线距地面的高度
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H=diag(ConductorY);
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r=0.03/2*eye(length(ConductorX));%导线自几何均距
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MirrorConductorX=[-9,0,9];
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MirrorConductorY=-[14.5,14.5,14.5];
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%电压(复数,先左后右)
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%单回
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Volt=[525; 525*exp(1j*240*pi/180); 525*exp(1j*120*pi/180);];
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%形成电位系数矩阵
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H=diag([28.5, 21, 27.5, 28.5, 21, 27.5 ]);
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r=diag([0.2,0.2,0.2,0.2,0.2,0.2]);
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Dcomma=[0,58.5,55,62.42,58.98,55.5;
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58.5,0,51.5,58.98,55.5,52.1;
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55, 51.5 0,55.5,52.1 48.7;
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62.42,58.98,55.55,0,58.5,55;
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58.98,55.55,52.13,58.5,0,51.5;
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55.55,52.13,48.73,55,51.5,0];
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D=[ 0 3.51 7.02 7.2 8.27 10.4;
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3.51 0 3.51 8.27 7.8 8.8
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7.02 3.51 0 10.4 8.8 8.4
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7.2 8.27 10.48 0 3.5 7.02
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8.27 7.8 8.8 3.51 0 3.51
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10.4 8.8 8.4 7.02 3.51 0];
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%导线与镜像的距离
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cplxConductorXY=ConductorX+1j*ConductorY;
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cplxMirrorConductorXY=MirrorConductorX+1j*MirrorConductorY;
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matCplxConductorXY=repmat(cplxConductorXY,length(ConductorX),1);
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matCplxMirrorConductorXY=repmat(conj(cplxMirrorConductorXY'),1,length(ConductorX));
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conductor2MirrorDistance=abs(matCplxConductorXY-matCplxMirrorConductorXY);
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conductor2MirrorDistance=conductor2MirrorDistance-diag(diag(conductor2MirrorDistance));
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%导线与导线的距离
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conductor2conductorDistance=matCplxConductorXY-conj(matCplxConductorXY');
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conductor2conductorDistance=conductor2conductorDistance-diag(diag(conductor2conductorDistance));
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%计算电位系数
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eslong=1;
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P=1/pi/eslong*log(2*H./r);
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P(isnan(P))=0;
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P2=1/pi/eslong*log(Dcomma./D);
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P1=1/pi/eslong*log(2*H./r);
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P1(isnan(P1))=0;
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P2=1/pi/eslong*log(conductor2MirrorDistance./conductor2conductorDistance);
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P2(isnan(P2))=0;
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P=P+P2;
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P=P1+P2;
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%求电荷
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QRI=inv(P2)*Volt;
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%导线坐标
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ABCx=[-3.6; -3.9; -4.2; 3.6; 3.9; 4.2];
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ABCy=[31; 27.5; 24; 31; 27.5; 24];
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%求地面场强
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plotY=zeros(60,1);
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plotX=zeros(60,1);
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for I=-30:30
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x=I;
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y=0;
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ERy=sum( (ABCy-y)./( (ABCy-y).^2+(ABCx-x).^2 ).*real(QRI)./2/pi/eslong );
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EIy=sum( (ABCy-y)./( (ABCy-y).^2+(ABCx-x).^2 ).*imag(QRI)./2/pi/eslong );
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ERx=sum( (ABCx-x)./( (ABCy-y).^2+(ABCx-x).^2 ).*real(QRI)./2/pi/eslong );
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EIx=sum( (ABCx-x)./( (ABCy-y).^2+(ABCx-x).^2 ).*imag(QRI)./2/pi/eslong );
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E=sqrt(ERy.^2+EIy.^2+ERx.^2+EIx.^2);
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plotY(I+31)=E;
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plotX(I+31)=x;
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end
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plot(plotX,plotY);
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QRI=P\Volt;
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%求电场强度
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