61 lines
2.3 KiB
Matlab
61 lines
2.3 KiB
Matlab
function Jacob=jacobian_M(Busnum,Volt,Y,Angle,AngleIJMat)
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%**************************************************************************
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% 程序功能 : 子函数——形成雅可比矩阵Jacobian
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% 编 者：
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% 编制时间：2010.12
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%**************************************************************************
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%% 分别求雅克比矩阵的子阵H,L,N,J及有功无功分量P,Q
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temp1=-Volt'*Volt.*Y;
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AngleIJ=AngleIJMat-Angle;
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temp11=Volt'*ones(1,Busnum).*Y;
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temp2=sum(temp1.*sin(AngleIJ),2);
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temp22 = sum(temp11.*sin(AngleIJ),2);
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temp3 = sum(temp1.*cos(AngleIJ),2);
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temp33 = sum(temp11.*cos(AngleIJ),2);
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temp4=diag(temp2);
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temp44=diag(temp22);
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temp5=diag(temp3);
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temp55=diag(temp33);
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%计算Lii的累加项
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t1=ones(Busnum,1)*Volt.*Y;
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t2=sum(t1.*sin(AngleIJ),2);
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t3=sum(t1.*cos(AngleIJ),2);
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t4=diag(t2);
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t5=diag(t3);
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H = temp1.*sin(AngleIJ)-temp4;%
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L = -temp11.*sin(AngleIJ);%
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%L(1:Busnum,1:Busnum)=-temp44+;
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L=L-t4;
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N=-temp11.*cos(AngleIJ);%
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%N(1:Busnum,1:Busnum)=-temp55-diag(diag(temp11.*cos(Angle) ) );
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N=N-t5;
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J = -temp1.*cos(AngleIJ)+temp5;%
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%%
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%Q = Q0+temp2'; %求有功分量P
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%P = P0+temp3'; %求无功分量Q
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%% 处理平衡节点和pv节点
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% H(:,Balance) = 0;
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% H(Balance,:) = 0;
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% H(Balance,Balance) = 100; % 平衡节点对应的对角元素置一个有限数
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% L(:,PVi) = 0;
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% L(PVi,:) = 0;
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% L = L+sparse(PVi,PVi,ones(1,length(PVi)),Busnum,Busnum); % PV节点对应的对角元素置为1
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% J(:,Balance) = 0;
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% J(PVi,:) = 0;
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% N(:,PVi) = 0;
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% N(Balance,:) = 0;
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% Q(PVi) = 0; % 将pv节点的无功不平衡分量置零
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% P(Balance) = 0; % 平衡节点的有功功率不平衡分量置零
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%% 合成PQ和雅可比矩阵
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t1=zeros(2*Busnum);
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t1(1:2:2*Busnum,1:2:2*Busnum)=H;
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t1(1:2:2*Busnum,2:2:2*Busnum)=N;
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t1(2:2:2*Busnum,1:2:2*Busnum)=J;
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t1(2:2:2*Busnum,2:2:2*Busnum)=L;
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% t1(1:)
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% PQ = cat(2,P,Q); % 形成功率不平衡分量列向量
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%Jacob = cat(1,cat(2,H,N),cat(2,J,L)); % 形成Jacobian矩阵
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Jacob=t1;
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end |