初步完成了只用正序的

Signed-off-by: dugg@lab-desk <dugg@lab-desk>

run.m

@@ -1,5 +1,5 @@
 %% 利用先把负荷转换为电流的方法。这个方法要求知道电压量。
-% 
+%
 clc
 clear
 lineZ=readLineZ('feeder13\lineParameter.txt');
@@ -41,9 +41,11 @@ If2=sparse(busNum,1);
 Vf0=sparse(busNum,1);
 If0=sparse(busNum,1);
 %准备序矩阵
+%平衡节点置0置1
 fsY2(Balance,:)=0;
 fsY2(:,Balance)=0;
 fsY2=fsY2+sparse(Balance,Balance,ones(length(Balance),1),busNum,busNum);
+%平衡节点置0置1
 fsY0(Balance,:)=0;
 fsY0(:,Balance)=0;
 fsY0=fsY0+sparse(Balance,Balance,ones(length(Balance),1),busNum,busNum);
@@ -69,6 +71,57 @@ while(k<=kmax && maxD> EPS)
     iterPhaseASpotLoadQ=phaseASpotLoadQ+imag(SA);
     iterPhaseBSpotLoadQ=phaseBSpotLoadQ+imag(SB);
     iterPhaseCSpotLoadQ=phaseCSpotLoadQ+imag(SC);
+    %全部转换为负荷电流
+    CurpA=conj((iterPhaseASpotLoadP+1j*iterPhaseASpotLoadQ)./VoltpA);
+    CurpB=conj((iterPhaseBSpotLoadP+1j*iterPhaseBSpotLoadQ)./VoltpB);
+    CurpC=conj((iterPhaseCSpotLoadP+1j*iterPhaseCSpotLoadQ)./VoltpC);
+    %转换为序电流
+    f012=Tp2f*conj([CurpA';CurpB';CurpC']);
+    %把三序电流分离出来
+    If0=conj(f012(1,:)');
+    If1=conj(f012(2,:)');
+    If2=conj(f012(3,:)');
+    %得到三序电压
+    V012=Tp2f*conj([VoltpA';VoltpB';VoltpC']);
+    %分离出三序电压
+    V0=conj(V012(1,:)');
+    V1=conj(V012(2,:)');
+    V2=conj(V012(3,:)');
+    %试着算一下正序电流
+    fsY11*V1;
+    %形成负荷序电流的测量值
+    mIf0=If0;
+    mIf1=If1;
+    mIf1(1)=0.02;
+    mIf1(3)=0.03;
+    Loadi=[ 1 2 3];
+    mIf2=If2;
+    %计算
+    fsY11=fsY11+sparse(Balance,Balance,ones(length(Balance),1),busNum,busNum);%这里要置0，置1，否则是奇异的
+    %%做最小二乘法
+    %先做正序的
+    Z=[%这里要加-号，因为用的Z是注入电流
+        -real(mIf1(Loadi));
+        -imag(mIf1(Loadi));
+        ];
+    H=fsY11(Loadi,:);
+    H=[
+        -real(H),imag(H);
+        -imag(H),-real(H);
+        ];
+    %     J=fsY11(Loadi,:);
+    %     J=[
+    %         conj(-real(J))',-conj(imag(J))';
+    %         conj(imag(J))',-conj(real(J))';
+    %     ];
+    J=conj(H');
+    %J*Z+J*H*X=0 ->J*H*X=-J*Z
+    X=-inv(J*H)*J*Z;
+    %     X=inv(conj(H)'*H)*conj(H)'*Z;
+    Xr=X(1:length(X)/2);
+    Xi=X(length(X)/2+1:end);
+    Xri=Xr+1j*Xi;
+    fsY11*Xri;
     [dP, dQ, YdotSinVolt, YdotCosVolt, diag_Volt_YdotSin, diag_Volt_YdotCos]=Unbalance(Balance,busNum, ...
         PQi,PG,QG,QGi,iterPD,iterQD,Vmf1,Vaf1,fsY1amp,fsY1ang,r,c,Vf2,If2,Vf0,If0);%不平衡量
     maxD=max(abs([dP;dQ;]));
@@ -79,15 +132,9 @@ while(k<=kmax && maxD> EPS)
     %转换为三相电压
     VoltpABC=Tp2f\conj([ Vf0'; (Vmf1.*exp(1j*Vaf1))'; Vf2']);%用Tp2f\ 代替Tf2p*
     VoltpA=conj(VoltpABC(1,:)');
-    CurpA=-conj((iterPhaseASpotLoadP+1j*iterPhaseASpotLoadQ)./VoltpA);
-    VoltpB=conj(VoltpABC(2,:)');
-    CurpB=-conj((iterPhaseBSpotLoadP+1j*iterPhaseBSpotLoadQ)./VoltpB);
-    VoltpC=conj(VoltpABC(3,:)');
-    CurpC=-conj((iterPhaseCSpotLoadP+1j*iterPhaseCSpotLoadQ)./VoltpC);
-    f012=Tp2f*conj([CurpA';CurpB';CurpC']);
-    If0=conj(f012(1,:)');
-    If1=conj(f012(2,:)');
-    If2=conj(f012(3,:)');
+    
+    
+    
     If0(Balance)=0;
     If2(Balance)=0;
     %Vf0=fsY0\If0;
@@ -116,8 +163,8 @@ ub=checkSSatisfied(Balance,phaseABCY,VoltpABC, ...
     phaseASpotLoadP,phaseBSpotLoadP,phaseCSpotLoadP, ...
     phaseASpotLoadQ,phaseBSpotLoadQ,phaseCSpotLoadQ );
 fprintf('最大不平衡量为%f\n\n',full(max(abs(ub))))
-fprintf('开始牛顿法迭代\n');
 %% 用牛顿法求解begin
+% fprintf('开始牛顿法迭代\n');
 % [r,c,GB]=find(phaseABCY);
 % Y=abs(phaseABCY);
 % Yangle=angle(GB);