修复了合并线路后没用重新计算阻抗的问题

Signed-off-by: dmy@lab <dmy@lab.lab>

testHasttable/element/line.cpp

@@ -8,12 +8,17 @@ Line::Line(const QPair<QString,QString>& fromTo, ACLineSegment* ac, QObject *par
 }
 
 
+void Line::re_extract()
+{
+    this->extract();
+}
 
 void Line::extract()
 {
     //用YJV22-3x240
     ACLineSegment *ac=this->ac;
     double length=ac->getLength();
+    this->length=length;
 //    if((int)length==0)
 //    {
 //        std::cout<<"line length zeros "<<ac->getID().toStdString()<<std::endl;
@@ -31,5 +36,5 @@ void Line::extract()
     this->g2=g0*length/1000;
     this->b1=b0*length/1000;
     this->b2=b0*length/1000;
-    this->length=length/1000;
+
 }

testHasttable/element/line.h

@@ -8,6 +8,7 @@ class Line:public Branch
 {
 public:
     Line(const QPair<QString, QString> &fromTo, ACLineSegment* ac,QObject* parent=0);
+    void re_extract();
     double length;
     ACLineSegment *ac;